flynnsta02oyt3kr
flynnsta02oyt3kr flynnsta02oyt3kr
  • 02-11-2017
  • Chemistry
contestada

how many molecules are in 79g of fe2o3

Respuesta :

dangerousmattoycs4v
dangerousmattoycs4v dangerousmattoycs4v
  • 02-11-2017
Convert grams —> mols and then mols —> atoms

We know that there are 6.02 x 10^23 atoms/mol

And we know that there are about 160 grams of fe2o3 per mol

So (79g fe2o3)/(160 g/mol) = .49 mol fe2o3

Now we use avogadro’s number to do

(.49 mol fe2o3)/(6.02 x 10^23 atoms/mol) = the answer.

I’ll leave the easy math to you.
Answer Link

Otras preguntas

1.10% in decimal form
The one selected is wrong please help meee!
66 1/2% of x is 5. What is x?
how did third parties impact the election of 1860 (the civil war) ? two sentence answer
Discuss the democratization of American society. How did Americans' values change in the early nineteenth century? How did these values express themselves in Am
I NEED HELP PLEASE ANYONE
x + 2y = −6 in slope intercept form
Connoisseurship concerns itself with the study of Function Content Style Iconography
How do people demonstrate that popular sovereignty exists?
could someone do a step-by-step? 2x < x − 4 ≤ 3x + 8