Answer:
2
Step-by-step explanation:
[tex]\dfrac{8\sqrt{6}}{4\sqrt{6}}=\dfrac{8}{4}\cdot\dfrac{\sqrt{6}}{\sqrt{6}}=\dfrac{8}{4}=2[/tex]
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Maybe you mean ...
[tex]\dfrac{\sqrt[8]{6}}{\sqrt[4]{6}}=6^{\frac{1}{8}-\frac{1}{4}}=6^{-\frac{1}{8}}\\\\=\dfrac{6^{\frac{7}{8}}}{6}=\dfrac{\sqrt[8]{279936}}{6}[/tex]
