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03-06-2018
Mathematics

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Find the value of x in each case. PLEASE SHOW WORK!!!

Find the value of x in each case PLEASE SHOW WORK class=

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03-06-2018

Hi,
[tex]mes \widehat{BCE}=90^o-64^o=36^o\\ mes \widehat{ABE}=mes \widehat{BEC}+mes \widehat{BCE}\\ 3x=x+36\\ \Rightarrow\ 3x-x=36\\ \Rightarrow\ 2x=36\\ \Rightarrow\ x= \dfrac{36}{2} \\ \Rightarrow\ \boxed{x=18}\\ [/tex]

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