Respuesta :

gmany
[tex]f(x)=\boxed{1}x^5-3x^2+3x+\boxed{14}[/tex]

The potential rational zeros are divisors of 14:

[tex]\pm1;\ \pm2;\ \pm7;\ \pm14[/tex]

and the quotient p/q where p is a divisor of 1, and q is a divisor of 14:

[tex]\pm\dfrac{1}{2};\ \pm\dfrac{1}{7};\ \pm\dfrac{1}{14}[/tex]

Otras preguntas