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  • 14-07-2018
  • Mathematics
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Find the differential of the function l=xze^(-y^2-z^2)

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LammettHash
LammettHash LammettHash
  • 14-07-2018

[tex]I=xze^{-y^2-z^2}[/tex]


[tex]\mathrm dI=\dfrac{\partial I}{\partial x}\,\mathrm dx+\dfrac{\partial I}{\partial y}\,\mathrm dy+\dfrac{\partial I}{\partial z}\,\mathrm dz[/tex]


[tex]\mathrm dI=ze^{-y^2-z^2}\,\mathrm dx-2yxze^{-y^2-z^2}\,\mathrm dy+\left(x-2xz^2\right)e^{-y^2-z^2}\,\mathrm dz[/tex]

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