ImmortalFusedZamasu ImmortalFusedZamasu

01-08-2018
Mathematics

contestada

Solve For Z

A. 12

B.
[tex]4 \sqrt{7} [/tex]
C.
[tex]3 \sqrt{7} [/tex]
D. 51

Solve For ZA 12B tex4 sqrt7 texC tex3 sqrt7 texD 51 class=

Respuesta :

06-08-2018

Triangle ABC and triangle BCD are similar, therefore the sides are in proportion:

[tex]\dfrac{z}{9+7}=\dfrac{7}{z}[/tex]

cross multiply

[tex]z^2=16\cdot7\to z=\sqrt{16\cdot7}\\\\z=\sqrt{16}\cdot\sqrt7\\\\z=4\sqrt7[/tex]

Answer: B. 4√7

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