Bananajane
Bananajane Bananajane
  • 01-08-2018
  • Mathematics
contestada

What is the extreme of the following function
[tex]y = - x^{2} + 2[/tex]

Respuesta :

Mustela Mustela
  • 01-08-2018

It is a quadratic function with graph as parabola

and its maximum lies at the vertex

So we have to find the vertex

So firstly compare it with y=ax^2 +bx +c

we get a=-1 and b=0 and c=2

So to find the vertex (h,k)

[tex] h=\frac{-b}{2a}= \frac{-0}{2(-1)}= 0 [/tex]

to find k , plug h=0 inplace of x in the function

[tex] h=-(0)^2 +2 = 2 [/tex]

So vertex is (0,2)

And the maximum value is (0,2) which is the extreme of the function

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