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13-09-2018
Chemistry

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Raw one valid lewis structure (including all lone pair electrons and any formal charges) for ch2n2. Assume the atoms are arranged as shown below. H c n n h

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13-09-2018

In the trial structure (1st image below), every atom has an octet.

Valence electrons = 20

Valence electrons available = 4 + 2 +10 = 16

The trial structure has 4 electrons too many. The actual structure must have two double bonds or one triple bond.

The second image shows two possible Lewis structures.

Ver imagen znk

Ver imagen znk

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