rangingruby10164 rangingruby10164
  • 15-10-2018
  • Mathematics
contestada

Solve for x. 2x2+4x−1=0 Enter your answers in the boxes.

Respuesta :

FoxWoods FoxWoods
  • 15-10-2018

[tex]2 \times 2 + 4x - 1 = 0 \\ 4 + 4x - 1 = 0 \\ 4x - 1 = - 4 \\ 4x = - 3 \\ x = - \frac{3}{4} [/tex]
Answer Link
wifilethbridge wifilethbridge
  • 01-10-2019

Answer:

0.2247,-2.2247

Step-by-step explanation:

Equation : [tex]2x^2+4x-1 =0[/tex]

We are supposed to find the values of x .

General form of equation : [tex]ax^2+bx+c=0[/tex]

Formula : [tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

a = 2

b = 4

c = -1

So, [tex]x=\frac{-4 \pm \sqrt{4^2-4(2)(-1)}}{2(2)}[/tex]

[tex]x=0.2247,-2.2247 [/tex]

Hence the values of x are 0.2247,-2.2247

Answer Link

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