[tex]-15x+4\leq109\qquad\text{subtract 4 from both sides}\\\\-15x\leq105\qquad\text{change the signs}\\\\15x\geq-105\qquad\text{divide both sides by 15}\\\\\boxed{x\geq-7}\\or\\-6x+70>-2\qquad\text{subtract 70 from both sides}\\\\-6x>-72\qquad\text{change the signs}\\\\6x<72\qquad\text{divide both sides by 6}\\\\\boxed{x<12}\\\\Answer:\ \boxed{-7\leq x<12}[/tex]
