Answer:
Your answer of option b is right.
Step-by-step explanation:
Given that a sinesoidal function has maximum 12 and minimum -6
Hence centre line would be average of these two.
Centre line is [tex]y=\frac{12-6}{2} =3[/tex]
i.e. f(x) = a sin (bx+c)+3
Since amplitude = 12-3 =9 we have a = 9
i.e. f(x) = 9 sin (bx+c)+3
Frequency is given as 3, period = 1/3
This gives b = 6pi
f(0) = y intercept =
9sin(c)+3 =3
This gives c=0
Hence correct equation is
[tex]y =9sin 6 \pi x+3[/tex]
