Answer:
A and B
Step-by-step explanation:
Given
8 > 3 + [tex]\frac{t}{4}[/tex]
Isolate the term in t by subtracting 3 from both sides
5 > [tex]\frac{t}{4}[/tex] ( multiply both sides by 4 )
20 > t ⇒ t < 20
t = 12 and t = 16 are both less than 20
Hence A and B
