Respuesta :

Answer:

{4, - 1}

Step-by-step explanation:

Given

2y² - 6y - 8 = 0 ← in standard form

with a = 2, b = - 6, c = - 8

Using the quadratic formula to solve for y

y = ( - (- 6) ± [tex]\sqrt{(-6)^2-(4(2)(-8)}[/tex] ) / (2 × 2)

  = ( 6 ± [tex]\sqrt{36+64}[/tex] ) / 4

  = ( 6 ± [tex]\sqrt{100}[/tex] ) / 4

  = ( 6 ± 10 ) / 4

x = [tex]\frac{6+10}{4}[/tex] = [tex]\frac{16}{4}[/tex] = 4

OR

x = [tex]\frac{6-10}{4}[/tex] = [tex]\frac{-4}{4}[/tex] = - 1

Solution is { 4, - 1 }