Answer:
h(1)= 1
h(4)=5
Step-by-step explanation:
Given
h(x)= x^3 for 1≤x≤3
and
h(x)=5 x>3
Now finding h(1), i.e when x=1
x=1 lies in the range 1≤x≤3 hence putting value x=1 in x^3
h(1)= 1^3
= 1
Now finding h(4), i.e when x=4
x=1 lies in the range x<3 hence putting value x=4 in h(x)=5
h(4)= 5 !
