For this case we must find an expression equivalent to:
[tex]\frac {10x ^ 6y ^ {12}} {- 5x ^ {- 2} y^ {- 6}}[/tex]
We have to:
[tex]\frac {10} {- 5} = - 2[/tex]
Now, by definition of division of powers of equal base, we put the same base and subtract the exponents. Rewriting the expression we have:
[tex]-2x ^ {6 - (- 2)} y^ {12 - (- 6)} =\\-2x ^ {6 + 2} y ^ {12 + 6} =\\-2x ^ 8y ^ {18}[/tex]
Answer:
Option B
