deegau
deegau deegau
  • 14-08-2019
  • Mathematics
contestada

Tan A+ Tan (90-A) = secA .sec (90-A)​

Respuesta :

jimrgrant1 jimrgrant1
  • 14-08-2019

Answer:

see explanation

Step-by-step explanation:

Using the cofunction identities

tan(90 - A) = cotA and cscA = sec(90- A)

Consider the left side

tanA + tan(90 - A)

= tanA + cotA

= [tex]\frac{sinA}{cosA}[/tex] + [tex]\frac{cosA}{sinA}[/tex]

= [tex]\frac{sin^2A+cos^2A}{cosAsinA}[/tex]

= [tex]\frac{1}{cosAsinA}[/tex]

= [tex]\frac{1}{cosA}[/tex] × [tex]\frac{1}{sinA}[/tex]

= secA × cscA

= secA. sec(90 - A) = right side ⇒ verified

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