Answer:
[tex]\Large \textnormal{The slope is \boxed{1}.}[/tex]
Step-by-step explanation:
To find the slope of (-1, 10) & (3,14), first you have to use the slope formula of [tex]\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex].
y2= 14
y1=10
x2=3
x1=(-1)
Solve.
[tex]\displaystyle \frac{14-10}{3-(-1)}=\frac{4}{4}=\boxed{1}[/tex]
In conclusion, the slope is 1, which is our answer.
