Enjay6371 Enjay6371
  • 13-09-2019
  • Physics
contestada

What magnitude charge creates a 4.80 N/C electric field at a point 3.60 m away?

Respuesta :

Xema8 Xema8
  • 16-09-2019

Answer:

Q = 6.9 X 10⁻⁹ C.

Explanation:

Electric field E due to a charge Q at distance r is given by the relation

E = k Q / r²

Here E = 4.8 , k = 9 x 10⁹ ; r = 3.6 m Q = ?

4.8 = [tex]\frac{9\times10^9\times Q}{(3.6)^2}[/tex]

Q = [tex]\frac{4.8\times(3.6)^2}{9\times10^9}[/tex]

Q = 6.9 X 10⁻⁹ C.

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