Answer:
De broglie wavelength = 4.17 pm
Explanation:
We have given mass of proton [tex]m=1.67\times 10^{-27}kg[/tex]
Speed of proton v [tex]v=9.50\times 10^{6}m/sec[/tex]
Plank's constant [tex]h=6.63\times 10^{-34}J-s[/tex]
We have to find de broglie wavelength
De broglie wavelength is given by [tex]\lambda =\frac{h}{mv}=\frac{6.63\times 10^{-34}}{1.67\times 10^{-27}\times 9.5\times 10^6}=4.17\times 10^{-12}m=4.17pm[/tex]
