tibbs6431 tibbs6431
  • 11-10-2019
  • Engineering
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Determine linear atomic density along 11011 direction of a FCC unit cell with a constant a (cube edge length).

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Netta00 Netta00
  • 11-10-2019

Answer:

[tex]LD=\dfrac{1}{\sqrt2 \ a}[/tex]

Explanation:

Given that

Unit cell is in FCC

Here given direction is not clear visible so we take direction [101].

We know that linear density(LD) given as

[tex]LD=\dfrac{Number\ of\ atoms\ in\ the\ direction\ vector}{d_{[101]}}[/tex]

So the number of atom will be 1 in direction  [101]

In FCC

[tex]a=2\sqrt2 \ r[/tex]

[tex]LD=\dfrac{1}{\sqrt2 \ a}[/tex]

[tex]LD=\dfrac{1}{4r}[/tex]

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