Whynot1316
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  • 11-10-2019
  • Mathematics
contestada

How to solve the inequality

[tex]\frac{5}{12} -\frac{x-3}{6} \leq \frac{x-2}{3}[/tex]

Respuesta :

Аноним Аноним
  • 11-10-2019

Answer:

x[tex]\geq[/tex] 19/6

Step-by-step explanation:

1. Multiply both sides by 6 (the LCM of 6,3)

5/2 + 3-x <= 2(x-2)

2. Simplify 5/2+3-x to 11/2-x

11/2 - x<=2 (x-2)

3. Expand.

11/2-x<= 2x-4

4. Add x to both sides.

11/2<= 2x-4+x

5. Simplify 2x-4+x to 3x-4.

11/2<=3x-4

6. Add 4 to both sides.

11/2+4<=3x

7. Simplify 11/2+4 to 19/2

19/2<=3x

8. Divide both sides by 3

19/2 /3 <=x

9. Simplify 19/2 /3 to 19/2*3

19/2*3<=x

10. Simplify 2*3 to 6

19/6<=x

11. Switch sides.

x>= 19/6

Hope this helps!

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