Answer with Step-by-step explanation:
We are given that a function
[tex]f(x)=5^{-x}+2[/tex]
Let [tex]y=f(x)=5^{-x}+2[/tex]
We have to sketch the graph.
Substitute x=0
Then we get
[tex]y=5^0+2=1+2=3[/tex]
When x tends to infinity
[tex]\lim_{x\rightarrow \infty}y=\lim_{x\rightarrow \infty}(5^{-x}+2)=2[/tex]
y-intercept of f(x) at y=3
Now, draw a line which cut the y-axis at y=3 and approach 2 when x approaches to infinity.
