mikemoss4328 mikemoss4328
  • 14-01-2020
  • Mathematics
contestada

Find an equation of the plane that passes through the origin and its perpendicular to the vector [1,-2,5]

Respuesta :

GreatB GreatB
  • 15-01-2020

Answer:

x - 2y + 5z = 0

Step-by-step explanation:

The standard equation is of the form, Ax + By + Cz = 0

The equation of the plane that passes through the origin(0, 0, 0)  and is perpendicular to [1, -2, 5] is

A = 1, B = -2, C = 5

x = y = z = 0 (at origin)

A(x-0) + B(y-0) + C(z-0) = 0

(x - 0) -2(y-0) + 5(z-0) = 0

x - 2y + 5z = 0

Answer Link

Otras preguntas

What was the importance of the Northwest Ordinance?
What is the krebs cycle??
what is the lcm of 2/3 and 1/6
What effect did technology have on World War I? Question 19 options: A. It enabled nations to defeat their enemies with few casualties. B. It enabled na
How was Germany similar to Italy in the 1800s?
If there is 4% increase in orbital radius...then by how much its time period will increase?
anonymous 3 years ago Which statement best describes a difference between Leonardo da Vinci's Virgin of the Rocks and Sofonisba Anguissola's The Chess Gam
During transcription, enzymes bind to a molecule of DNA. Then, the enzymes unwind and separate the DNA's double helical strands. As the molecule unwinds, comple
I'm not sure how to start. Can anyone help with a few letters? Once I get a start, I can finish
Given the system of equations: 2x + 2y = 16 6x + 4y = 38 What is the value of X? A. 13 B. -1 C. 3 D. 1/3