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A flywheel of J = 50 kg-m2 initially standing still is subjected to a constant torque. If the angular velocity reaches 20 Hz in 5 S, find the torque given to the flywheel.

Respuesta :

Answer:

[tex]\tau = 1256.5\ N.m[/tex]

Explanation:

given,

J = 50 kg-m²

frequency, f = 20 Hz

time ,t = 5 s

we know,

angular velocity = 2 π f

ω = 2 π x 20

ω = 125.66 rad/s

now, angular acceleration calculation

[tex]\alpha = \dfrac{\omega_f-\omega_i}{t}[/tex]

[tex]\alpha = \dfrac{125.66-0}{5}[/tex]

   α = 25.13 rad/s²

Torque given to the flywheel.

    [tex]\tau = I \alpha[/tex]

    [tex]\tau = 50\times 25.13[/tex]

    [tex]\tau = 1256.5\ N.m[/tex]

Torque of the given  flywheel is equal to [tex]\tau = 1256.5\ N.m[/tex]

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