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01-02-2020
Chemistry

contestada

Determine the concentrations of each ion present in 0.045 M Ca(NO3)2.

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Eduard22sly Eduard22sly

02-02-2020

Answer:

Ca(NO3)2. <==> Ca^2+ + 2(NO3)^-

Ca^2+ = 0.045 M

2(NO3)^- = 2(0.045) = 0.09M

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