The first diffraction minimum located at an angle of 5.40°.
Explanation:
Here the wavelength, λ = 565 nm = 565 × 10⁻⁹ m
Width of the slit, d = 0.00600 mm = 6 × 10⁻⁶ m
We need to find the angle as,
sin θ = mλ / d
We have to find the angle as,
θ = sin⁻¹ ( mλ / d )
Here m = 1,
θ = sin⁻¹ ( [tex]$\frac{1\times565 \times 10^{-9} }{6\times 10^{-6} }[/tex] )
= sin⁻¹(0.0942)
= 5.40°
So the first diffraction minimum located at an angle of 5.40°.
