bukarisheriff71
bukarisheriff71 bukarisheriff71
  • 01-05-2020
  • Mathematics
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help me please right away​

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nktselepov
nktselepov nktselepov
  • 01-05-2020

[tex] {t}^{2} = \frac{4b {x}^{2} }{k} \\ k {t}^{2} = 4b {x}^{2} \\ \frac{k {t}^{2} }{4b} = {x}^{2} \\ x = \sqrt{ \frac{k {t}^{2} }{4b} } = 0.5t \sqrt{ \frac{k}{b} } [/tex]

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