mcenaneykaitlyn4239 mcenaneykaitlyn4239
  • 13-05-2020
  • Mathematics
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Find the solution of Z^5=32 whose argument is strictly between 0 and 90 degrees

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xero099
xero099 xero099
  • 16-05-2020

Answer:

[tex]\|r\| = 32[/tex], [tex]\theta = 0\,rad[/tex]

Step-by-step explanation:

This complex expression is computed from the De Moivre expression:

[tex]z^{5} = 32\cdot (\cos 5x + i \cdot \sin 5x)[/tex]

Given that resultant expression is entirely real, the expression is simplified into this form:

[tex]32 = 32\cdot \cos 5x[/tex]

[tex]\cos 5x = 1[/tex]

The angle is 0 radians.

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