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12-06-2020
Mathematics

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The nth term of a sequence is represented by [tex]\frac{2n^4+25n^2+32n-15}{6n^4+2n^3-11n^2-2n+17}[/tex] . What is the limit of the nth term as x becomes increasingly large?

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27-08-2020

Answer:

2n3+8n2-32n=16

Step-by-step explanation:

[tex]2n3 +8n2-32n=16[/tex]

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