How do you rearrange the equation (2x) /(4pi) +((1-x) /2) =0 to solve for x?

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i1sajchrlShahamnsch i1sajchrlShahamnsch

02-09-2016
Mathematics

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How do you rearrange the equation (2x) /(4pi) +((1-x) /2) =0 to solve for x?

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how do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O

HomertheGenius HomertheGenius · Answer 1 · 2016-09-07T18:47:31+02:00

HomertheGenius HomertheGenius

07-09-2016

[tex] \frac{2x}{4 \pi } + \frac{1-x}{2} =0 \\ \frac{x}{2 \pi } + \frac{1-x}{2} = 0[/tex]
Then we will multiply both sides of the equation by 2 π :
x + π ( 1 - x ) = 0
x + π - π x = 0
x ( 1 - π ) = - π / · ( - 1 )
x ( π - 1 ) = π
x = π / ( π - 1 )

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