Noelia653 Noelia653
  • 03-07-2020
  • Mathematics
contestada

En el triángulo rectángulo ABC, recto en “B”, SI Tg C = 3/5, hallar el valor “cosec A”

Respuesta :

facundo3141592
facundo3141592 facundo3141592
  • 10-07-2020

Answer: Cosec(A) = 3.64

Step-by-step explanation:

Ok, tenemos un triangulo rectángulo.

Sabemos que B = 90° y que  

tg(C) = 3.5

entonces:

Atg(Tg(C)) = C = Atg(3.5) = 74.05°.

Nosotros también sabemos que la suma de todos los ángulos interiores de un triangulo es igual que 180°

entonces:

A + B + C = 180°

A + 90° + 74.05° = 180°

A = 180° - 90° - 74.05° = 15.95°

Entonces Cosec(A) = Cosec(15.95°) = 1/sin(15.95°) = 3.64

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