kantyisawesome kantyisawesome
  • 14-08-2020
  • Mathematics
contestada

Solve 64^x = 16^(x−1). (1 point) Select one: a. x = −2 b. x = −1 c. x = negative 1 over 4 d. x = negative 1 over 3

Respuesta :

hbj
hbj hbj
  • 14-08-2020

Answer:

a. x = -2

Step-by-step explanation:

64ˣ = 16⁽ˣ⁻¹)

64 = 4³

16 = 4²

4³⁽ˣ⁾ = 4²⁽ˣ⁻¹)

4³ˣ = 4²ˣ⁻²

3x = 2x - 2

x = -2

Answer Link
09pqr4sT
09pqr4sT 09pqr4sT
  • 14-08-2020

Answer:

[tex]\huge \boxed{x=-2}[/tex]

Step-by-step explanation:

64^x = 16^(x-1)

Rewrite the bases with base of 4.

(4^3)^x = (4^2)^(x-1)

Multiply exponents.

4^(3x) = 4^(2(x-1))

Cancel same bases.

3x = 2(x-1)

Expand brackets.

3x = 2x - 2

Subtract 2x from both sides.

x = -2

Answer Link

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