Answer:
(x+1)(x+15)
Step-by-step explanation:
[tex]x^2+16x+15\\\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(x^2+x\right)+\left(15x+15\right)\\\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2+x\mathrm{:\quad }x\left(x+1\right)\\\\\mathrm{Factor\:out\:}15\mathrm{\:from\:}15x+15\mathrm{:\\\quad }15\left(x+1\right)\\=x\left(x+1\right)+15\left(x+1\right)\\\\\mathrm{Factor\:out\:common\:term\:}x+1\\=\left(x+1\right)\left(x+15\right)[/tex]
