superion1677 superion1677
  • 11-09-2020
  • Mathematics
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Estellia
Estellia Estellia
  • 11-09-2020

Answer:

Third option: [tex]-10x^7y^2[/tex]

Step-by-step explanation:

[tex]12x^4\left(-\frac{5}{6}x^3y^2\right)[/tex]

Remove brackets:

[tex]12x^4\times-\frac{5}{6}x^3y^2[/tex]

Multiply the [tex]x^2[/tex]:

[tex]12\times-\frac{5}{6}x^{4+3}\times y^2[/tex]

[tex]12\times - \frac{5}{6}x^7y^2[/tex]

Multiply:

[tex]-\frac{5\times \:12x^7y^2}{6}[/tex]

[tex]-\frac{60x^7y^2}{6}[/tex]

Divide:

[tex]-10x^7y^2[/tex]

Answer Link
abdulazeez21
abdulazeez21 abdulazeez21
  • 11-09-2020

Answer:

the answer to your question is -10(x^7) (y^2)

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