barronomar777
barronomar777
14-09-2016
Mathematics
contestada
2x^{2} +4x+1=0
Solve for x.
Respuesta :
mpanderla95
mpanderla95
14-09-2016
2x^2 + 4x + 1 = 0
2x^2 + 4x + 1 - 1 = 0 - 1
2x^2 + 4x = -1
X(2x + 4) = -1
X = -1.
2x + 4 = -1
2x + 4 - 4 = -1 - 4
2x = -5
2x/2 = -5/2
X = -5/2.
I believe these are the solutions. If not you can use the quadratic formula to solve for the roots, solutions.
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