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A is an angle in standard position and satisfies the given conditions. Find the indicated trigonometric function value of A.
The terminal side of A is in quadrant II and lies on the line -7x - 5y = 0.
Find sec A.​

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sqdancefan

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Answer:

  sec(A) = -(1/5)√74

Step-by-step explanation:

Solving the equation for y, we have ...

  -7x = 5y

  -7/5x = y

The slope of this line (-7/5) is the tangent of the angle (A) it makes with the x-axis. The secant satisfies the relation ...

  sec(A)^2 = 1 + tan(A)^2

  sec(A) = √(1 +tan(A)^2)

  sec(A) = -√(1 +(-7/5)^2) = -√(74/25) . . . . secant is negative in 2nd quadrant

  sec(A) = -(1/5)√74

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