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The surface area of a right square pyramid is given by A=b2+2bh where b is the length of a side of the base and h is the slant height.solve the formula for h if b=3

Respuesta :

mathstudent55

Answer:

[tex] h = \dfrac{A - 9}{6} [/tex]

Step-by-step explanation:

A=b^2+2bh

b = 3

A = 3^2 + 2(3)h

A = 9 + 6h

6h = A - 9

[tex] h = \dfrac{A - 9}{6} [/tex]

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