Answer:
320 kg of iron(III) oxide contain 4007.76 moles of iron atom.
Explanation:
Given data:
Mass of iron(III) oxide = 320 kg (320000 g)
Number of moles of iron atoms = ?
Solution:
First of all we will calculate the number of moles of iron(III) oxide.
Number of moles = mass/molar mass
Number of moles = 320000 g/ 159.69 g/mol
Number of moles = 2003.88 mol
1 mole of Fe₂O₃ contain 2 moles of iron atom.
2003.88 moles of Fe₂O₃ contain,
2003.88 ×2 = 4007.76 moles of iron atom.
