nancyrj3018 nancyrj3018
  • 02-11-2020
  • Mathematics
contestada

Trapezoid JKLM with vertices J(-4,3), K(-2,7),

L(2,7), and M(3, 3): y = 1


Find JKLM

Respuesta :

ibiscollingwood ibiscollingwood
  • 03-11-2020

Answer:

The area of the given trapezoid is 22[tex]unit^2[/tex]

Step-by-step explanation:

We need to find the area of the trapezoid JKLM formed by the given coordinates which are

J(-4,3) K(-2,7) L(2,7) M (3,3)      

Area of trapezoid is given by = [tex]\frac{1}{2}* (sum of parallel side( a+b ))* height[/tex]

parallel points are k(-2,7) and L(2,7) , J (-4,3) and (3,3)

a= 4 ,b=7

height = 4

upon substituting these values in the equation

A=[tex]\frac{1}{2}*(11)*4[/tex] = 22[tex]unit^2[/tex]

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