addi5doty addi5doty

03-12-2020
Mathematics

contestada

Solve (y-4)^2+63=0 where y is a real number.

Respuesta :

Hrishii Hrishii

03-12-2020

Answer:

[tex] y = 4 + 3 \sqrt{7} i[/tex]

Step-by-step explanation:

[tex](y-4)^2+63=0 \\ \\ (y-4)^2 = - 63 \\ \\ (y-4)= \sqrt{ - 63} \\ \\ y - 4 = 3 \sqrt{7} i \\ \\ y = 4 + 3 \sqrt{7} i[/tex]

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