rubalcabajackie rubalcabajackie
  • 03-12-2020
  • Mathematics
contestada

solve 6x^2 - 12x + 24 = 0 by completing the square

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bridgetadeleye123
bridgetadeleye123 bridgetadeleye123
  • 03-12-2020

Answer: [tex]\quad x=1+\sqrt{3}i,\:x=1-\sqrt{3}i[/tex]

Step-by-step explanation: [tex]x_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:6\cdot \:24}}{2\cdot \:6}[/tex]

  • [tex]x_{1,\:2}=\frac{-\left(-12\right)\pm \:12\sqrt{3}i}{2\cdot \:6}[/tex]
  • [tex]x_1=\frac{-\left(-12\right)+12\sqrt{3}i}{2\cdot \:6},\:x_2=\frac{-\left(-12\right)-12\sqrt{3}i}{2\cdot \:6}[/tex]
  • [tex]x=1+\sqrt{3}i,\:x=1-\sqrt{3}i[/tex]

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