kellysalazar00 kellysalazar00
  • 13-12-2020
  • Mathematics
contestada

Does the MVT apply? Explain why or why not.
y=-x^2/x-1 ; [-1,1]

Does the MVT apply Explain why or why not yx2x1 11 class=

Respuesta :

leena
leena leena
  • 13-12-2020

Hi there!

[tex]\large\boxed{\text{No, it does not.}}[/tex]

[tex]y = \frac{x^{2} }{x-1}[/tex]

Looking at the equation, we can see that there is a discontinuity at x = 1 (Vertical Asymptote).

The interval given also includes x = 1 as an enclosed value.

Therefore, the MVT does not apply because the equation is not continuous on the interval [-1, 1].

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