Answer:
3.3792 g
Explanation:
The balanced equation for the reaction is given as;
2 C2H2(g) + 3 O2(g) --> 2 CO2(g) + 2 H2O(g)
From the reaction;
2 mol of C2H2 requires 3 mol of O2
2.0 g of C2H2
Number of moles = Mass / Molar mass = 2 / 26.04 = 0.07680 mol
5.0 g of O2
Number of moles = Mass / Molar mass = 5 / 32 = 0.15625 mol
The limiting reactant is; C2H2
2 mol of C2H2 produces 2 mol of CO2
0.07680 mol produces x
Solving for x;
x = 0.07680 mol
Mass = Molar mass * Number of moles = 44 g/mol * 0.07680 mol = 3.3792 g
