Answer:
t = 22.22 s
Step-by-step explanation:
Given that,
The initial speed of the train, u = 40 km/h
Acceleration of the train, a = 0.5 m/s²
Finally, it stops, v = 0
We need to find the time taken by it to stop. using first equation of motion to find it such that,
[tex]v=u+at\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{0-40\times \dfrac{5}{18}}{-0.5}\\\\t=22.22\ s[/tex]
So, it will take 22.22 seconds to stop.
