haleyissocool3716 haleyissocool3716
  • 13-04-2021
  • Mathematics
contestada

2. Given log35 = 1.465, approximate the value of log325.

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sqdancefan
sqdancefan sqdancefan
  • 14-04-2021

9514 1404 393

Answer:

  2.930

Step-by-step explanation:

The applicable rule of logarithms is ...

  log(a^b) = b·log(a)

___

Here, this means ...

  [tex]\log_3(25)=\log_3(5^2)=2\cdot\log_3(5)=2\cdot1.465\\\\\boxed{\log_3(25)=2.930}[/tex]

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