Given:
The length of diagonals of a rhombus are 12 ft and 5 ft.
To find:
The area of the rhombus
Solution:
Area of a rhombus is:
[tex]Area=\dfrac{d_1d_2}{2}[/tex]
Where, [tex]d_1,d_2[/tex] are two diagonals of the rhombus.
It is given that the length of diagonals of the rhombus are 12 ft and 5 ft.
Putting [tex]d_1=12,d_2=5[/tex], we get
[tex]Area=\dfrac{12\times 5}{2}[/tex]
[tex]Area=\dfrac{60}{2}[/tex]
[tex]Area=30[/tex]
Therefore, the area of the rhombus is 30 square ft.
