Answer:
<ABT = 43°
<TBC = 43°
Step-by-step explanation:
Given,
Line BT is the bisector of <ABC
So,
3x + 13 = 5x - 7
=> 13 + 7 = 5x - 3x
=> 20 = 2x
[tex] = > x = \frac{20}{2} [/tex]
=> x = 10
As,
We got the value of x = 10
Therefore,
<ABT = 3x + 13 °
= 3×10 + 13 °
= 30 + 13°
= 43°
<TBC = 5x - 7°
= 5 × 10 - 7°
= 50 - 7°
= 43°
Hence,
Value of <ABT = 43° and value of <TBC = 43° (Ans)
