mahmoodaaminah28 mahmoodaaminah28

01-05-2021
Mathematics

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Find the factors of x3−7x−6

(x+3)(x+2)(x−1)
(x−3)(x+2)(x+1)
(x−4)(x−2)(x+1)
(x−6)(x−1)(x+1)

Respuesta :

mhanifa mhanifa

01-05-2021

Answer:

B. (x−3)(x+2)(x+1)

Step-by-step explanation:

Possible options are 1 or 2 as each has odd number of negative coefficients.

Open parenthesis and verify:

(x+3)(x+2)(x−1) = ³ + 4x² + x - 6, false
(x−3)(x+2)(x+1) = x³ - 7x - 6, true

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