iriscantarero67 iriscantarero67
  • 14-06-2021
  • Mathematics
contestada

Find two consecutive positive integers such that the square of the
smaller integer is nineteen more than five times the larger integer.

Respuesta :

clarch19
clarch19 clarch19
  • 14-06-2021

Answer:

8 and 9

Step-by-step explanation:

let 'n' = smaller positive integer

let 'n+1' = larger

n² = 5(n+1)+19

n² = 5n + 5 + 19

n² = 5n + 24

n² - 5n - 24 = 0

(n-8)(n+3) = 0

n = 8  [this is the smaller positive integer]

n+1 = 9  [this is the larger positive integer]

n = -3  [this value can be discounted because it is not positive]

Answer Link

Otras preguntas

Can you help me with this one ? Factor 2x2 + 7x + 3.A.(2x + 1)(x + 3)B.(2x + 3)(x + 1)C.(2x + 5)(x + 1)D.The polynomial is prime.
Find the speed in degrees per minute of the minute hand of an accurate a clock.
Compare the adult frog to the tadpole.
When momentum is transferred from one object to another, the total amount of momentum in the system (is/ is not) conserved
what is 7/10 minus 1/2
Is the earth crust around earth is one solid piece true or false ?
what is one fifth of 15
how do you simplefly 2/3
the Romans told ancient stories or legends about their gods called
Which is greater 0.4 or 0.2