Answer:
Explanation:
The direction of the vector implies only its angle, not its magnitude. The direction of the vector is found in
[tex]tan^{-1}(\frac{y}{x})[/tex] so
[tex]tan^{-1}(\frac{11.1}{-43.0})=-14.5[/tex] but since we are in QII (where x is negative and y is positive) we have to add 180 to this number to get a direction of 165.5 degrees
